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In this section we will derive the formulas used to get the
area between two curves and the volume of a solid of revolution.
Area Between Two
Curves
We will start with the formula for determining the area
between 
and 
on the interval [a,b]. We will also assume
that 
on [a,b].
We will now proceed much as we did when we looked that the Area Problem in the Integrals Chapter. We will first divide up the interval into n equal subintervals each with length,
Next, pick a point in each subinterval, 
,
and we can then use rectangles on each interval as follows.

The height of each of these rectangles is given by,
and the area of each rectangle is then,
So, the area between the two curves is then approximated by,
The exact area is,
Now, recalling the definition
of the definite integral this is nothing more than,
The formula above will work provided the two functions are
in the form 
and 
. However, not all functions are in that
form. Sometimes we will be forced to
work with functions in the form between 
and 
on the interval [c,d] (an interval of y
values…).
When this happens the derivation is identical. First we will start by assuming that 
on [c,d]. We can then divide up the interval into equal
subintervals and build rectangles on each of these intervals. Here is a sketch of this situation.

Following the work from above, we will arrive at the
following for the area,
So, regardless of the form that the functions are in we use
basically the same formula.
Volumes for Solid of
Revolution
Before deriving the formula for this we should probably
first define just what a solid of revolution is. To get a solid of revolution we start out
with a function, 
,
on an interval [a,b].

We then rotate this curve about a given axis to get the
surface of the solid of revolution. For
purposes of this derivation let’s rotate the curve about the x-axis.
Doing this gives the following three dimensional region.

We want to determine the volume of the interior of this
object. To do this we will proceed much
as we did for the area between two curves case.
We will first divide up the interval into n subintervals of width,
We will then choose a point from each subinterval, 
.
Now, in the area between two curves case we approximated the
area using rectangles on each subinterval.
For volumes we will use disks on each subinterval to approximate the
area. The area of the face of each disk
is given by 
and the volume of each disk is
Here is a sketch of this,

The volume of the region can then be approximated by,
The exact volume is then,
So, in this case the volume will be the integral of the
cross-sectional area at any x, 
. Note as well that, in this case, the
cross-sectional area is a circle and we could go farther and get a formula for
that as well. However, the formula above
is more general and will work for any way of getting a cross section so we will
leave it like it is.
In the sections where we actually use this formula we will
also see that there are ways of generating the cross section that will actually
give a cross-sectional area that is a function of y instead of x. In these cases the formula will be,
In this case we looked at rotating a curve about the x-axis, however, we could have just as
easily rotated the curve about the y-axis. In fact we could rotate the curve about any
vertical or horizontal axis and in all of these, case we can use one or both of
the following formulas.