Calculus I - Common Graphs

Section 1.10 : Common Graphs

Basic problem solution....

13. Without using a graphing calculator sketch the graph of ${\left( {x + 1} \right)^2} + {\left( {y - 5} \right)^2} = 9$.

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This is just a circle in standard form and so we can see that it has a center of $\left( { - 1,5} \right)$ and a radius of 3. Here is a quick sketch of the circle.

$The graph of the circle ${\left( {x + 1} \right)^2} + {\left( {y - 5} \right)^2} = 9$. The circle has center (-1,5) and radius 3, so its leftmost point is (-4,5), its rightmost point is (2,5), its lowest point is (-1,2) and its highest point is (-1,8).$