Paul's Online Math Notes
     
 
Online Notes / Calculus I (Notes) / Applications of Derivatives / Differentials

Internet Explorer 10 & 11 Users : If you are using Internet Explorer 10 or Internet Explorer 11 then, in all likelihood, the equations on the pages are all shifted downward. To fix this you need to put your browser in Compatibility View for my site. Click here for instructions on how to do that. Alternatively, you can also view the pages in Chrome or Firefox as they should display properly in the latest versions of those browsers without any additional steps on your part.

In this section we’re going to introduce a notation that we’ll be seeing quite a bit in the next chapter.  We will also look at an application of this new notation.

 

Given a function  we call dy and dx differentials and the relationship between them is given by,

 

 

 

Note that if we are just given  then the differentials are df and dx and we compute them in the same manner.

 

 

 

Let’s compute a couple of differentials.

 

Example 1  Compute the differential for each of the following.

(a)  

(b)  

(c)  

 

Solution

Before working any of these we should first discuss just what we’re being asked to find here.  We defined two differentials earlier and here we’re being asked to compute a differential. 

 

So, which differential are we being asked to compute?  In this kind of problem we’re being asked to compute the differential of the function.  In other words, dy for the first problem, dw for the second problem and df for the third problem.

 

Here are the solutions.  Not much to do here other than take a derivative and don’t forget to add on the second differential to the derivative.

 

(a)  

 

(b)  

 

(c)  

 

 

There is a nice application to differentials.  If we think of  as the change in x then  is the change in y corresponding to the change in x.  Now, if  is small we can assume that .  Let’s see an illustration of this idea.

 

Example 2  Compute dy and  if  as x changes from  to .

 

Solution

First let’s compute actual the change in y, .

 

                        

 

Now let’s get the formula for dy.

                                                   

 

Next, the change in x from  to  is  and so we then assume that .  This gives an approximate change in y of,

 

                                  

 

We can see that in fact we do have that  provided we keep  small.

 

We can use the fact that  in the following way.

 

Example 3  A sphere was measured and its radius was found to be 45 inches with a possible error of no more that 0.01 inches.  What is the maximum possible error in the volume if we use this value of the radius?

 

Solution

First, recall the equation for the volume of a sphere.

                                                                 

Now, if we start with  and use  then  should give us maximum error.

 

So, first get the formula for the differential.

                                                               

 

Now compute dV.

                                          

 

The maximum error in the volume is then approximately 254.47 in3.

 

Be careful to not assume this is a large error.  On the surface it looks large, however if we compute the actual volume for  we get .  So, in comparison the error in the volume is,

                                                    

 

That’s not much possible error at all!


Online Notes / Calculus I (Notes) / Applications of Derivatives / Differentials

[Contact Me] [Links] [Privacy Statement] [Site Map] [Terms of Use] [Menus by Milonic]

© 2003 - 2014 Paul Dawkins