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Online Notes / Calculus III / Applications of Partial Derivatives / Relative Minimums and Maximums
Calculus III

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In this section we are going to extend one of the more important ideas from Calculus I into functions of two variables.  We are going to start looking at trying to find minimums and maximums of functions.  This in fact will be the topic of the following two sections as well.

 

In this section we are going to be looking at identifying relative minimums and relative maximums.  Recall as well that we will often use the word extrema to refer to both minimums and maximums. 

 

The definition of relative extrema for functions of two variables is identical to that for functions of one variable we just need to remember now that we are working with functions of two variables.  So, for the sake of completeness here is the definition of relative minimums and relative maximums for functions of two variables.

 

Definition

1.      A function  has a relative minimum at the point  if  for all points  in some region around .

2.      A function  has a relative maximum at the point  if  for all points  in some region around .

 

Note that this definition does not say that a relative minimum is the smallest value that the function will ever take.  It only says that in some region around the point  the function will always be larger than .  Outside of that region it is completely possible for the function to be smaller.  Likewise, a relative maximum only says that around  the function will always be smaller than .  Again, outside of the region it is completely possible that the function will be larger.

 

Next we need to extend the idea of critical points up to functions of two variables.  Recall that a critical point of the function  was a number  so that either  or  doesn’t exist.  We have a similar definition for critical points of functions of two variables.

 

Definition

The point  is a critical point (or a stationary point) of  provided one of the following is true,

  1.  (this is equivalent to saying that  and  ),
  2.  and/or  doesn’t exist.

 

To see the equivalence in the first part let’s start off with  and put in the definition of each part.

 

 

The only way that these two vectors can be equal is to have   and  ). In fact, we will use this definition of the critical point more than the gradient definition since it will be easier to find the critical points if we start with the partial derivative definition.

 

Note as well that BOTH of the first order partial derivatives must be zero at .  If only one of the first order partial derivatives are zero at the point then the point will NOT be a critical point.

 

We now have the following fact that, at least partially, relates critical points to relative extrema.

 

Fact

If the point  is a relative extrema of the function  then  is also a critical point of  and in fact we’ll have .

 

Proof

This is a really simple proof that relies on the single variable version that we saw in Calculus I version, often called Fermat’s Theorem.

 

Let’s start off by defining  and suppose that  has a relative extrema at .  However, this also means that  also has a relative extrema (of the same kind as  ) at .  By Fermat’s Theorem we then know that .  But we also know that  and so we have that .

 

If we now define  and going through exactly the same process as above we will see that .

 

So, putting all this together means that   and so  has a critical point at .   

Pf_Box

 

 

Note that this does NOT say that all critical points are relative extrema.  It only says that relative extrema will be critical points of the function.  To see this let’s consider the function

 

 

 

The two first order partial derivatives are,

 

 

 

The only point that will make both of these derivatives zero at the same time is  and so  is a critical point for the function.  Here is a graph of the function.

 

RelExt_G1

 

Note that the axes are not in the standard orientation here so that we can see more clearly what is happening at the origin, i.e. at .  If we start at the origin and move into either of the quadrants where both x and y are the same sign the function increases.  However, if we start at the origin and move into either of the quadrants where x and y have the opposite sign then the function decreases.  In other words, no matter what region you take about the origin there will be points larger than  and points smaller than