Section 1.7 : Complex Numbers
Perform the indicated operation and write your answer in standard form.
- \(2i + \left( { - 8 - 15i} \right)\)
- \(\left( {12 + i} \right) + \left( {9 + 2i} \right)\)
- \(4 - \left( {3 - 20i} \right)\)
- \(\displaystyle \left( {\frac{3}{2} - \frac{1}{3}i} \right) - \left( {\frac{5}{4} + \frac{7}{9}i} \right)\)
- \(\left( {3 + 2i} \right) + \left( {3 - 8i} \right) - \left( { - 4 - 7i} \right)\)
- \( - 2i\left( {9 + i} \right)\)
- \(\left( {10 + 3i} \right)\left( { - 1 + 7i} \right)\)
- \({\left( {6 + 2i} \right)^2}\)
- \(\left( {2 - 14i} \right)\left( {2 + 14i} \right)\)
- \(\displaystyle \left( {2 - \frac{1}{2}i} \right)\left( { - \frac{1}{3} + 5i} \right)\)
- \(\left( {9 + 2i} \right)\left( {1 - 3i} \right)\left( {5 + 4i} \right)\)
- \(\displaystyle \frac{{1 + i}}{{7 - i}}\)
- \(\displaystyle \frac{{2 + 4i}}{{ - 9 + 3i}}\)
- \(\displaystyle \frac{{6i}}{{ - 4 - 7i}}\)
- \(\displaystyle \frac{{12 - 2i}}{{9i}}\)
- \(\displaystyle \frac{{4 + 5i}}{{4 - 5i}}\)
- \(\displaystyle \frac{{i\left( {10 - 12i} \right)}}{{\left( {2 + i} \right)\left( { - 1 + 4i} \right)}}\)