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Section 1.1 : Integer Exponents

3. Evaluate the following expression and write the answer as a single number without exponents.

$\frac{{{4^0} \cdot {2^{ - 2}}}}{{{3^{ - 1}} \cdot {4^{ - 2}}}}$ Show Solution

There is not really a whole lot to this problem. All we need to do is the evaluations recalling the proper order of operations.

$\frac{{{4^0} \cdot {2^{ - 2}}}}{{{3^{ - 1}} \cdot {4^{ - 2}}}} = \frac{{{4^0} \cdot {3^1} \cdot {4^2}}}{{{2^2}}} = \frac{{\left( 1 \right) \cdot \left( 3 \right) \cdot \left( {16} \right)}}{4} = \require{bbox} \bbox[2pt,border:1px solid black]{{12}}$

It is almost always going to be best to first get rid of negative exponents prior to doing any of the rest of the evaluation work. Also, donâ€™t forget to reduce any resultant fractions down as much as possible.