Paul's Online Notes
Home / Algebra / Polynomial Functions / Partial Fractions
Show Mobile Notice Show All Notes Hide All Notes
Mobile Notice
You appear to be on a device with a "narrow" screen width (i.e. you are probably on a mobile phone). Due to the nature of the mathematics on this site it is best views in landscape mode. If your device is not in landscape mode many of the equations will run off the side of your device (should be able to scroll to see them) and some of the menu items will be cut off due to the narrow screen width.

### Section 5.5 : Partial Fractions

8. Determine the partial fraction decomposition of each of the following expression.

$\frac{{3{x^2} + 7x + 28}}{{x\left( {{x^2} + x + 7} \right)}}$

Show All Steps Hide All Steps

Start Solution

The first step is to determine the form of the partial fraction decomposition. For this problem the partial fraction decomposition is,

$\frac{{3{x^2} + 7x + 28}}{{x\left( {{x^2} + x + 7} \right)}} = \frac{A}{x} + \frac{{Bx + C}}{{{x^2} + x + 7}}$ Show Step 2

The LCD for this expression is $$x\left( {{x^2} + x + 7} \right)$$. Adding the terms back up gives,

$\frac{{3{x^2} + 7x + 28}}{{x\left( {{x^2} + x + 7} \right)}} = \frac{{A\left( {{x^2} + x + 7} \right) + \left( {Bx + C} \right)\left( x \right)}}{{x\left( {{x^2} + x + 7} \right)}}$ Show Step 3

Setting the numerators equal gives,

$3{x^2} + 7x + 28 = A\left( {{x^2} + x + 7} \right) + \left( {Bx + C} \right)\left( x \right)$ Show Step 4

Because we have an unfactorable quadratic equation here the method we used in the first problems from this section won’t work. So, we will need to multiply everything out and collect like terms.

\begin{align*}3{x^2} + 7x + 28 & = A{x^2} + Ax + 7A + B{x^2} + Cx\\ & = \left( {A + B} \right){x^2} + \left( {A + C} \right)x + 7A\end{align*} Show Step 5

We now need to set coefficients equal. Remember this just means setting the coefficient of the $${x^2}$$ on both sides equal and similarly for the coefficients of the $$x$$ and the constants. Doing this gives,

\begin{align*}A + B & = 3\\ A + C & = 7\\ 7A & = 28\end{align*} Show Step 6

As mentioned in the notes this is a system of equations that we really haven’t talked about how to solve in general, but that is not a real problem. From the third equation we can see that we must have $$A = 4$$.

Once we have this we only need to plug that into the first two equations to determine the values of $$B$$ and $$C$$. Here is that work,

$\begin{array}{l}{4 + B = 3}\\{4 + C = 7}\end{array}\hspace{0.25in} \to \hspace{0.25in}\begin{array}{l}{B = - 1}\\{C = 3}\end{array}$ Show Step 7

The partial fraction decomposition is then,

$\require{bbox} \bbox[2pt,border:1px solid black]{{\frac{{3{x^2} + 7x + 28}}{{x\left( {{x^2} + x + 7} \right)}} = \frac{4}{x} + \frac{{3 - x}}{{{x^2} + x + 7}}}}$