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Section 2.4 : Equations With More Than One Variable

2. Solve \(\displaystyle Q = \frac{{6h}}{{7s}} + 4\left( {1 - h} \right)\) for \(s\).

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Start Solution

Note that there quite a few solution “paths” that you can take to get the solution to this problem. For this solution let’s first clear the denominator out by multiplying both sides by 7\(s\).

\[\begin{align*}\left( Q \right)\left( {7s} \right) & = 7s\left( {\frac{{6h}}{{7s}} + 4\left( {1 - h} \right)} \right)\\ 7sQ & = 6h + 28s\left( {1 - h} \right)\end{align*}\] Show Step 2

Now let’s get all the terms with \(s\) on one side and the terms without \(s\) on the other side. We’ll also factor the \(s\) out when we’re done as well. Doing this gives,

\[\begin{align*}7sQ - 28s\left( {1 - h} \right) & = 6h\\ \left[ {7Q - 28\left( {1 - h} \right)} \right]s & = 6h\end{align*}\] Show Step 3

Finally, all we need to do is divide by both sides by the coefficient of the \(s\) to get,

\[\require{bbox} \bbox[2pt,border:1px solid black]{{s = \frac{{6h}}{{7Q - 28\left( {1 - h} \right)}}}}\]

Note that depending upon the path you chose for your solution you may have something slightly different for your answer. However, you could do some manipulation of your answer to make it look like mine (or you could manipulate mine to make it look like yours).