I have been informed that on March 7th from 6:00am to 6:00pm Central Time Lamar University will be doing some maintenance to replace a faulty UPS component and to do this they will be completely powering down their data center.
Unfortunately, this means that the site will be down during this time. I apologize for any inconvenience this might cause.
Paul
February 18, 2026
Section 3.9 : Chain Rule
11. Differentiate \(F\left( y \right) = \ln \left( {1 - 5{y^2} + {y^3}} \right)\) .
For this problem the outside function is (hopefully) clearly the logarithm and the inside function is the stuff inside of the logarithm. The derivative is then,
\[F^{\prime}\left( y \right) = \frac{1}{{1 - 5{y^2} + {y^3}}}\left( { - 10y + 3{y^2}} \right) = \require{bbox} \bbox[2pt,border:1px solid black]{{\frac{{ - 10y + 3{y^2}}}{{1 - 5{y^2} + {y^3}}}}}\]With logarithm problems remember that after differentiating the logarithm (i.e. the outside function) you need to substitute the inside function into the derivative. So, instead of getting just,
\[\frac{1}{y}\]we get the following (i.e. we plugged the inside function into the derivative),
\[\frac{1}{{1 - 5{y^2} + {y^3}}}\]Then, we can’t forget of course to multiply by the derivative of the inside function.