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Section 1.10 : Common Graphs

Without using a graphing calculator sketch the graph of \(h\left( x \right) = \cos \left( {x + \frac{\pi }{2}} \right)\).

Show Solution

Recall the basic Algebraic transformations. If we know the graph of \(g\left( x \right)\) then the graph of \(g\left( {x + c} \right)\) is simply the graph of \(g\left( x \right)\) shifted right by \(c\) units if \(c < 0\) or shifted left by \(c\) units if \(c > 0\).

So, in our case if \(g\left( x \right) = \cos \left( x \right)\) we can see that,

\[h\left( x \right) = \cos \left( {x + \frac{\pi }{2}} \right) = g\left( {x + \frac{\pi }{2}} \right)\]

and so the graph we’re being asked to sketch is the graph of the cosine function shifted left by \(\frac{\pi }{2}\) units.

Here is the graph of \(h\left( x \right) = \cos \left( {x + \frac{\pi }{2}} \right)\) and note that to help see the transformation we have also sketched in the graph of \(g\left( x \right) = \cos \left( x \right)\).

The graph of \(h\left( x \right) = \cos \left( {x + \frac{\pi }{2}} \right)\), drawn as a solid red curve, along with the graph of \(g\left( x \right) = \cos \left( x \right)\), drawn as a dashed gray curve, for \( - 2\pi \le x \le 2\pi \).  Both curves oscillate between -1 and 1.  Arrows point to a peak on each curve.  The graph of \(g\left( x \right)\) has a peak at \(x = 0\) and the graph of \(h\left( x \right)\) has a peak at \(x = - \frac{\pi }{2}\), so the graph of \(h\left( x \right)\) is the graph of \(g\left( x \right)\) shifted left \(\frac{\pi }{2}\) units.