Section 5.3 : Substitution Rule for Indefinite Integrals
14. Evaluate \( \displaystyle \int{{\frac{{\csc \left( x \right)\cot \left( x \right)}}{{2 - \csc \left( x \right)}}\,dx}}\).
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In this case it looks like we should use the following as our substitution.
\[u = 2 - \csc \left( x \right)\]Show Step 2
Because we need to make sure that all the \(x\)’s are replaced with \(u\)’s we need to compute the differential so we can eliminate the \(dx\) as well as the remaining \(x\)’s in the integrand.
\[du = \csc \left( x \right)\cot \left( x \right)dx\]Recall that, in most cases, we will also need to do a little manipulation of the differential prior to doing the substitution. In this case we don’t need to do that.
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Doing the substitution and evaluating the integral gives,
\[\int{{\frac{{\csc \left( x \right)\cot \left( x \right)}}{{2 - \csc \left( x \right)}}\,dx}} = \int{{\frac{1}{u}\,du}} = \ln \left| u \right| + c\]Show Step 4
Finally, don’t forget to go back to the original variable!
\[\int{{\frac{{\csc \left( x \right)\cot \left( x \right)}}{{2 - \csc \left( x \right)}}\,dx}} = \require{bbox} \bbox[2pt,border:1px solid black]{{\ln \left| {2 - \csc \left( x \right)} \right| + c}}\]