Section 14.2 : Gradient Vector, Tangent Planes and Normal Lines
- Find the tangent plane and normal line to \({x^2}y = 4z{{\bf{e}}^{x + y}} - 35\) at \(\left( {3, - 3,2} \right)\). Solution
- Find the tangent plane and normal line to \(\displaystyle \ln \left( {\frac{x}{{2y}}} \right) = {z^2}\left( {x - 2y} \right) + 3z + 3\) at \(\left( {4,2, - 1} \right)\). Solution