I have been informed that on March 7th from 6:00am to 6:00pm Central Time Lamar University will be doing some maintenance to replace a faulty UPS component and to do this they will be completely powering down their data center.
Unfortunately, this means that the site will be down during this time. I apologize for any inconvenience this might cause.
Paul
February 18, 2026
If you are looking for some problems with solutions you can find some by clicking on the "Practice Problems" link above.
Section 1.1 : Functions
For problems 1 – 6 the given functions perform the indicated function evaluations.
- \(f\left( x \right) = 10x - 3\)
- \(f\left( { - 5} \right)\)
- \(f\left( 0 \right)\)
- \(f\left( 7 \right)\)
- \(f\left( {{t^2} + 2} \right)\)
- \(f\left( {12 - x} \right)\)
- \(f\left( {x + h} \right)\)
- \(h\left( y \right) = 4{y^2} - 7y + 1\)
- \(h\left( 0 \right)\)
- \(h\left( { - 3} \right)\)
- \(h\left( 5 \right)\)
- \(h\left( {6z} \right)\)
- \(h\left( {1 - 3y} \right)\)
- \(h\left( {y + k} \right)\)
- \(g\left( t \right) = \displaystyle \frac{{t + 5}}{{1 - t}}\)
- \(g\left( 0 \right)\)
- \(g\left( 4 \right)\)
- \(g\left( { - 7} \right)\)
- \(g\left( {{x^2} - 5} \right)\)
- \(g\left( {t + h} \right)\)
- \(g\left( {4\sqrt t + 9} \right)\)
- \(f\left( z \right) = \sqrt {4z + 5} \)
- \(f\left( 0 \right)\)
- \(f\left( { - 1} \right)\)
- \(f\left( { - 2} \right)\)
- \(f\left( {5 - 12y} \right)\)
- \(f\left( {2{z^2} + 8} \right)\)
- \(f\left( {z + h} \right)\)
- \(\displaystyle z\left( x \right) = \frac{{\sqrt {{x^2} + 9} }}{{4x + 8}}\)
- \(z\left( 4 \right)\)
- \(z\left( { - 4} \right)\)
- \(z\left( 1 \right)\)
- \(z\left( {2 - 7x} \right)\)
- \(z\left( {\sqrt {3x + 4} } \right)\)
- \(z\left( {x + h} \right)\)
- \(\displaystyle Y\left( t \right) = \sqrt {3 - t} - \frac{t}{{2t + 5}}\)
- \(Y\left( 0 \right)\)
- \(Y\left( 7 \right)\)
- \(Y\left( { - 4} \right)\)
- \(Y\left( {5 - t} \right)\)
- \(Y\left( {{t^2} - 10} \right)\)
- \(Y\left( {6t - {t^2}} \right)\)
The difference quotient of a function \(f\left( x \right)\) is defined to be,
\[\frac{{f\left( {x + h} \right) - f\left( x \right)}}{h}\]For problems 7 – 13 compute the difference quotient of the given function.
- \(Q\left( t \right) = 4 - 7t\)
- \(g\left( t \right) = 42\)
- \(H\left( x \right) = 2{x^2} + 9\)
- \(z\left( y \right) = 3 - 8y - {y^2}\)
- \(g\left( z \right) = \sqrt {4 + 3z} \)
- \(\displaystyle y\left( x \right) = \frac{{ - 4}}{{1 - 2x}}\)
- \(\displaystyle f\left( t \right) = \frac{{{t^2}}}{{t + 7}}\)
For problems 14 – 21 determine all the roots of the given function.
- \(y\left( t \right) = 40 + 3t - {t^2}\)
- \(f\left( x \right) = 6{x^4} - 5{x^3} - 4{x^2}\)
- \(Z\left( p \right) = 6 - 11p - {p^2}\)
- \(h\left( y \right) = 4{y^6} + 10{y^5} + {y^4}\)
- \(g\left( z \right) = {z^7} + 6{z^4} - 16z\)
- \(f\left( t \right) = {t^{\frac{1}{2}}} - 8{t^{\frac{1}{4}}} + 15\)
- \(\displaystyle h\left( w \right) = \frac{w}{{4w + 5}} + \frac{{3w}}{{w - 8}}\)
- \(\displaystyle g\left( w \right) = \frac{w}{{w + 3}} - \frac{{w + 2}}{{4w - 1}}\)
For problems 22 – 30 find the domain and range of the given function.
- \(f\left( x \right) = {x^2} - 8x + 3\)
- \(z\left( w \right) = 4 - 7w - {w^2}\)
- \(g\left( t \right) = 3{t^2} + 2t - 3\)
- \(g\left( x \right) = 5 - \sqrt {2x} \)
- \(B\left( z \right) = 10 + \sqrt {9 + 7{z^2}} \)
- \(h\left( y \right) = 1 + \sqrt {6 - 7y} \)
- \(f\left( x \right) = 12 - 5\sqrt {2x + 9} \)
- \(V\left( t \right) = - 6\left| {5 - t} \right|\)
- \(y\left( x \right) = 12 + 9\left| {{x^2} - 1} \right|\)
For problems 31 – 51 find the domain of the given function.
- \(\displaystyle f\left( t \right) = \frac{{4 - 12t + 8{t^2}}}{{16t + 9}}\)
- \(\displaystyle v\left( y \right) = \frac{{{y^3} - 27}}{{4 - 17y}}\)
- \(\displaystyle g\left( x \right) = \frac{{3x + 1}}{{5{x^2} - 3x - 2}}\)
- \(\displaystyle h\left( t \right) = \frac{{{t^3} - {t^2} + 1 - 1}}{{35{t^3} + 2{t^4} - {t^5}}}\)
- \(\displaystyle f\left( z \right) = \frac{{{z^2} + z}}{{{z^3} - 9{z^2} + 2z}}\)
- \(\displaystyle V\left( p \right) = \frac{{3 - {p^4}}}{{4{p^2} + 10p + 2}}\)
- \(g\left( z \right) = \sqrt {{z^2} - 15} \)
- \(f\left( t \right) = \sqrt {36 - 9{t^2}} \)
- \(A\left( x \right) = \sqrt {15x - 2{x^2} - {x^3}} \)
- \(Q\left( y \right) = \sqrt {4{y^3} - 4{y^2} + y} \)
- \(\displaystyle P\left( t \right) = \frac{{{t^2} + 7}}{{\sqrt {6t - {t^2}} }}\)
- \(\displaystyle h\left( t \right) = \frac{{{t^2}}}{{\sqrt {5 + 3t - {t^2}} }}\)
- \(\displaystyle h\left( x \right) = \frac{6}{{\sqrt {{x^2} - 7x + 3} }}\)
- \(\displaystyle f\left( z \right) = \frac{{z + 1}}{{\sqrt {{z^4} - 6{z^3} + 9{z^2}} }}\)
- \(S\left( t \right) = \sqrt {8 - t} + \sqrt {2t} \)
- \(g\left( x \right) = \sqrt {5x - 8} - 2\sqrt {x + 9} \)
- \(h\left( y \right) = \sqrt {49 - {y^2}} - \frac{y}{{\sqrt {4y - 12} }}\)
- \(\displaystyle A\left( x \right) = \frac{{x + 1}}{{x - 4}} + 4\sqrt {{x^2} + 10x + 9} \)
- \(\displaystyle f\left( t \right) = \frac{8}{{{t^2} - 3t - 4}} + \frac{3}{{\sqrt {12 - 7t - 3{t^2}} }}\)
- \(\displaystyle R\left( x \right) = \frac{3}{{{x^4} + {x^2}}} + \sqrt[5]{{{x^2} - x - 6}}\)
- \(C\left( z \right) = {z^3} - \sqrt[4]{{{z^6} + {z^2}}}\)
For problems 52 – 55 compute \(\left( {f \circ g} \right)\left( x \right)\) and \(\left( {g \circ f} \right)\left( x \right)\) for each of the given pairs of functions.
- \(f\left( x \right) = 5 + 2x\), \(g\left( x \right) = 8 - 23x\)
- \(f\left( x \right) = \sqrt {2 - x} \), \(g\left( x \right) = 2{x^2} - 9\)
- \(f\left( x \right) = 2{x^2} + x - 4\), \(g\left( x \right) = 7x - {x^2}\)
- \(\displaystyle f\left( x \right) = \frac{x}{{3 + 2x}}\), \(g\left( x \right) = 8 + 5x\)