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### Section 13.7 : Directional Derivatives

For problems 1 – 4 determine the gradient of the given function.

1. $$f\left( {x,y} \right) = {y^3}{x^5} + \ln \left( {xy} \right)$$
2. $$f\left( {x,y} \right) = {{\bf{e}}^{\frac{x}{y}}} + {y^4}\sin \left( {xy} \right)$$
3. $$\displaystyle f\left( {x,y,z} \right) = 4z - \frac{{{y^4}}}{{2{z^3}}} + \sqrt {{x^3}} \left( {z - 1} \right)$$
4. $$\displaystyle f\left( {x,y,z} \right) = \cos \left( {\frac{{xy}}{z}} \right) + {z^3}{y^2}x$$

For problems 5 – 8 determine $${D_{\vec u}}f$$ for the given function in the indicated direction.

1. $$f\left( {x,y} \right) = \ln \left( {2xy} \right) - \sin \left( {{x^2} + {y^2}} \right)$$ in the direction of $$\vec v = \left\langle {7, - 3} \right\rangle$$
2. $$f\left( {x,y} \right) = 4{x^2}{y^3} - \sqrt {2x + 5y}$$ in the direction of $$\vec v = \left\langle { - 1,4} \right\rangle$$
3. $$\displaystyle f\left( {x,y,z} \right) = 8x{y^2} - \frac{{5{z^2}}}{x} + {y^4}$$ in the direction of $$\vec v = \left\langle { - 4,1,2} \right\rangle$$
4. $$\displaystyle f\left( {x,y,z} \right) = \frac{{3x}}{{{y^2} - {z^3}}} + 5{x^2} - 8y$$ in the direction of $$\vec v = \left\langle {0,3, - 2} \right\rangle$$
5. Determine $${D_{\vec u}}f\left( { - 1,4,6} \right)$$ for $$f\left( {x,y,z} \right) = {{\bf{e}}^{x\,y{\,^2}}} + 4z{y^3}$$ direction of $$\vec v = \left\langle {2, - 3,6} \right\rangle$$.
6. Determine $${D_{\vec u}}f\left( {8,1,2} \right)$$ for $$\displaystyle f\left( {x,y,z} \right) = \ln \left( {\frac{x}{z}} \right) + \ln \left( {\frac{z}{y}} \right) + {y^2}x$$ direction of $$\vec v = \left\langle {1,5,2} \right\rangle$$.

For problems 11 – 13 find the maximum rate of change of the function at the indicated point and the direction in which this maximum rate of change occurs.

1. $$f\left( {x,y} \right) = {{\bf{e}}^{4x\,y}}$$ at $$\left( {6, - 2} \right)$$
2. $$f\left( {x,y,z} \right) = {x^2}{y^4} - 3{z^2}x$$ at $$\left( {1, - 6,3} \right)$$
3. $$\displaystyle f\left( {x,y,z} \right) = \ln \left( {\frac{{2x + 3y}}{z}} \right)$$ at $$\left( {2,7,4} \right)$$
4. Given $$\displaystyle \vec u = \left\langle { - \frac{3}{5}, - \frac{4}{5}} \right\rangle$$, $$\displaystyle \vec v = \left\langle {\frac{4}{{\sqrt {20} }},\frac{2}{{\sqrt {20} }}} \right\rangle$$, $$\displaystyle \vec w = \left\langle { - \frac{3}{{\sqrt {11} }}, - \frac{2}{{\sqrt {11} }}} \right\rangle$$, $$\displaystyle {D_{\vec u}}\left( { - 1,4} \right) = \frac{{14}}{5}$$ and $$\displaystyle {D_{\vec v}}\left( { - 1,4} \right) = - \frac{{22}}{{\sqrt {20} }}$$ determine the value of $${D_{\vec w}}\left( { - 1,4} \right)$$.
5. Given $$\displaystyle \vec u = \left\langle {\frac{1}{{\sqrt {15} }},\frac{4}{{\sqrt {15} }}} \right\rangle$$, $$\displaystyle \vec v = \left\langle { - \frac{3}{{\sqrt {34} }}, - \frac{5}{{\sqrt {34} }}} \right\rangle$$, $$\displaystyle \vec w = \left\langle { - \frac{1}{{\sqrt 2 }},\frac{1}{{\sqrt 2 }}} \right\rangle$$, $$\displaystyle {D_{\vec u}}\left( {0,1} \right) = \frac{{18}}{{\sqrt {15} }}$$ and $$\displaystyle {D_{\vec v}}\left( {0,1} \right) = - \frac{{40}}{{\sqrt {34} }}$$ determine the value of $${D_{\vec w}}\left( {0,1} \right)$$.