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Section 1.5 : Factoring Polynomials
10. Factor the following polynomial.
\[5{x^2} + 14x - 3\]Show All Steps Hide All Steps
Start SolutionThere are only two positive factors of 5 so the initial form for the factoring will be,
\[\left( {5x + \underline {\,\,\,\,\,} } \right)\left( {x + \underline {\,\,\,\,\,} } \right)\]and the factors of -3 are,
\[\left( { - 1} \right)\left( 3 \right)\,\hspace{0.25in}\left( 1 \right)\left( { - 3} \right)\] Show Step 2After some trial and error we see that the correct factoring will then be,
\[5{x^2} + 14x - 3 = \require{bbox} \bbox[2pt,border:1px solid black]{{\left( {5x - 1} \right)\left( {x + 3} \right)}}\]