I have been informed that on March 7th from 6:00am to 6:00pm Central Time Lamar University will be doing some maintenance to replace a faulty UPS component and to do this they will be completely powering down their data center.
Unfortunately, this means that the site will be down during this time. I apologize for any inconvenience this might cause.
Paul
February 18, 2026
Section 6.2 : Logarithm Functions
9. Without using a calculator determine the exact value of \({\log _2} \displaystyle \frac{1}{8}\).
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Converting the logarithm to exponential form gives,
\[{\log _2}\frac{1}{8} = ?\hspace{0.25in} \Rightarrow \hspace{0.25in}{2^?} = \frac{1}{8}\] Show Step 2Now, we know that if we raise an integer to a negative exponent we’ll get a fraction and so we must have a negative exponent and then we know that \({2^3} = 8\). Therefore, we can see that \({2^{ - 3}} = \frac{1}{8}\) and so we must have,
\[\require{bbox} \bbox[2pt,border:1px solid black]{{{{\log }_2}\frac{1}{8} = - 3}}\]