I have been informed that on March 7th from 6:00am to 6:00pm Central Time Lamar University will be doing some maintenance to replace a faulty UPS component and to do this they will be completely powering down their data center.
Unfortunately, this means that the site will be down during this time. I apologize for any inconvenience this might cause.
Paul
February 18, 2026
Section 1.1 : Review : Functions
26. Find the domain of \(g\left( x \right) = \sqrt {25 - {x^2}} \).
Show SolutionIn this case we need to avoid square roots of negative numbers so we need to require,
\[25 - {x^2} \ge 0\]Note that once we have the original inequality written down we can do a little rewriting of things as follows to make things a little easier to see.
\[{x^2} \le 25\hspace{0.25in}\hspace{0.25in} \Rightarrow \hspace{0.25in}\,\,\,\,\, - 5 \le x \le 5\]At this point it should be pretty easy to find the values of \(x\) that will keep the quantity under the radical positive or zero so we won’t need to do a number line or sign table to determine the range.
The domain is then,
\[{\mbox{Domain : }} - 5 \le x \le 5\]