Paul's Online Notes
Home / Calculus I / Derivatives / Higher Order Derivatives
Show All Notes Hide All Notes

Section 3.12 : Higher Order Derivatives

2. Determine the fourth derivative of \(V\left( x \right) = {x^3} - {x^2} + x - 1\)

Show All Steps Hide All Steps

Start Solution

Not much to this problem other than to take four derivatives so each step will show each successive derivative until we get to the fourth. The first derivative is then,

\[V'\left( x \right) = 3{x^2} - 2x + 1\] Show Step 2

The second derivative is,

\[V''\left( x \right) = 6x - 2\] Show Step 3

The third derivative is,

\[V'''\left( x \right) = 6\] Show Step 4

The fourth, and final derivative for this problem, is,

\[\require{bbox} \bbox[2pt,border:1px solid black]{{{V^{\left( 4 \right)}}\left( x \right) = 0}}\]

Note that we could have just as easily used the Fact from the notes to arrive at this answer in one step.