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Section 3.12 : Higher Order Derivatives

7. Determine the second derivative of \(z = \ln \left( {7 - {x^3}} \right)\)

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Not much to this problem other than to take two derivatives so each step will show each successive derivative until we get to the second. The first derivative is then,

\[\frac{{dz}}{{dx}} = \frac{{ - 3{x^2}}}{{7 - {x^3}}}\] Show Step 2

Do not forget that often we will end up needing to do a quotient rule in the second derivative even though we did not need to do that in the first derivative. The second derivative is then,

\[\frac{{{d^2}z}}{{d{x^2}}} = \frac{{ - 6x\left( {7 - {x^3}} \right) - \left( { - 3{x^2}} \right)\left( { - 3{x^2}} \right)}}{{{{\left( {7 - {x^3}} \right)}^2}}} = \require{bbox} \bbox[2pt,border:1px solid black]{{\frac{{ - 42x - 3{x^4}}}{{{{\left( {7 - {x^3}} \right)}^2}}}}}\]