I have been informed that on March 7th from 6:00am to 6:00pm Central Time Lamar University will be doing some maintenance to replace a faulty UPS component and to do this they will be completely powering down their data center.
Unfortunately, this means that the site will be down during this time. I apologize for any inconvenience this might cause.
Paul
February 18, 2026
Section 5.1 : Indefinite Integrals
7. Determine \(h\left( t \right)\) given that \(h'\left( t \right) = {t^4} - {t^3} + {t^2} + t - 1\).
We know that indefinite integrals are asking us to undo a differentiation to so all we are really being asked to do here is evaluate the following indefinite integral.
\[h\left( t \right) = \int{{h'\left( t \right)\,dt}} = \int{{{t^4} - {t^3} + {t^2} + t - 1\,dt}} = \require{bbox} \bbox[2pt,border:1px solid black]{{\frac{1}{5}{t^5} - \frac{1}{4}{t^4} + \frac{1}{3}{t^3} + \frac{1}{2}{t^2} - t + c}}\]Don’t forget the “+c”! Remember that the original function may have had a constant on it and the “+c” is there to remind us of that.