I have been informed that on March 7th from 6:00am to 6:00pm Central Time Lamar University will be doing some maintenance to replace a faulty UPS component and to do this they will be completely powering down their data center.
Unfortunately, this means that the site will be down during this time. I apologize for any inconvenience this might cause.
Paul
February 18, 2026
Section 3.13 : Logarithmic Differentiation
4. Find the first derivative of \(g\left( w \right) = {\left( {3w - 7} \right)^{4w}}\).
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Start SolutionWe just need to do some logarithmic differentiation so take the logarithm of both sides and do a little simplifying.
\[\ln \left[ {g\left( w \right)} \right] = \ln \left[ {{{\left( {3w - 7} \right)}^{4w}}} \right] = 4w\,\,\ln \left( {3w - 7} \right)\] Show Step 2Use implicit differentiation to differentiate both sides with respect to \(w\). Don’t forget to product rule the right side.
\[\frac{{g'\left( w \right)}}{{g\left( w \right)}} = 4\ln \left( {3w - 7} \right) + 4w\frac{3}{{3w - 7}} = 4\ln \left( {3w - 7} \right) + \frac{{12w}}{{3w - 7}}\] Show Step 3Finally, solve for the derivative and plug in the equation for \(g\left( w \right)\) .
\[\begin{align*}g'\left( w \right) & = g\left( w \right)\left[ {4\ln \left( {3w - 7} \right) + \frac{{12w}}{{3w - 7}}} \right]\\ & = \require{bbox} \bbox[2pt,border:1px solid black]{{{{\left( {3w - 7} \right)}^{4w}}\left[ {4\ln \left( {3w - 7} \right) + \frac{{12w}}{{3w - 7}}} \right]}}\end{align*}\]