Paul's Online Notes
Paul's Online Notes
Home / Calculus II / 3-Dimensional Space / Vector Functions
Show Mobile Notice Show All Notes Hide All Notes
Mobile Notice
You appear to be on a device with a "narrow" screen width (i.e. you are probably on a mobile phone). Due to the nature of the mathematics on this site it is best viewed in landscape mode. If your device is not in landscape mode many of the equations will run off the side of your device (you should be able to scroll/swipe to see them) and some of the menu items will be cut off due to the narrow screen width.

Section 12.6 : Vector Functions

9. Write down the equation of the line segment starting at \(\left( {0,2, - 1} \right)\) and ending at\(\left( {7, - 9,2} \right)\).

Show Solution

There really isn’t a lot to do with this problem. All we need to do is use the formula we derived in the notes for this section.

The line segment is,

\[\require{bbox} \bbox[2pt,border:1px solid black]{{\vec r\left( t \right) = \left( {1 - t} \right)\left\langle {0,2, - 1} \right\rangle + t\left\langle {7, - 9,2} \right\rangle \,\,\,\,\,0 \le t \le 1}}\]

Don’t forget the limits on \(t\)! Without that you have the full line that goes through those two points instead of the line segment from \(\left( {0,2, - 1} \right)\) to \(\left( {7, - 9,2} \right)\).