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### Section 12.4 : Quadric Surfaces

3. Sketch the following quadric surface.

$z = \frac{{{x^2}}}{4} + \frac{{{y^2}}}{4} - 6$ Show Solution

This is an elliptic paraboloid that is centered on the $$z$$-axis. Because the $$x$$ and $$y$$ terms are positive we know that it will open upwards. The “-6” tells us that the surface will start at $$z = - 6$$. We can also say that because the coefficients of the $$x$$ and $$y$$ terms are identical the cross sections of the surface will be circles.

Here are a couple of sketches of the region. We’ve given them with the more traditional axes as well as “boxed” axes to help visualize the surface.  