Section 5.2 : Computing Indefinite Integrals
19. Evaluate \( \displaystyle \int{{\frac{6}{{{w^3}}} - \frac{2}{w}\,dw}}\).
Show SolutionThere really isn’t too much to do other than to evaluate the integral.
\[\int{{\frac{6}{{{w^3}}} - \frac{2}{w}\,dw}} = \int{{6{w^{ - 3}} - \frac{2}{w}\,dw}} = \require{bbox} \bbox[2pt,border:1px solid black]{{ - 3{w^{ - 2}} - 2\ln \left| w \right| + c}}\]