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Section 1.5 : Factoring Polynomials
13. Factor the following polynomial.
\[{x^2} + 14x + 49\] Show SolutionWe can do this in the manner of the previous problems if we wanted to. On the other hand we can notice that the constant is a perfect square and that \(2\left( 7 \right) = 14\) and so we can see that this is one of the special forms.
Therefore, the factoring of this polynomial is,
\[{x^2} + 14x + 49 = \require{bbox} \bbox[2pt,border:1px solid black]{{{{\left( {x + 7} \right)}^2}}}\]Note that while you don’t need necessarily need to know the special forms if you do and can easily recognize them it will make the factoring easier.