Paul's Online Notes
Paul's Online Notes
Home / Calculus I / Integrals / Definition of the Definite Integral
Show Mobile Notice Show All Notes Hide All Notes
Mobile Notice
You appear to be on a device with a "narrow" screen width (i.e. you are probably on a mobile phone). Due to the nature of the mathematics on this site it is best viewed in landscape mode. If your device is not in landscape mode many of the equations will run off the side of your device (you should be able to scroll/swipe to see them) and some of the menu items will be cut off due to the narrow screen width.

Section 5.6 : Definition of the Definite Integral

9. For \( \displaystyle \int_{0}^{5}{{ - 4x\,dx}}\) sketch the graph of the integrand and use the area interpretation of the definite integral to determine the value of the integral.

Show All Steps Hide All Steps

Start Solution

Here is the graph of the integrand, \(f\left( x \right) = - 4x\) on the interval \(\left[ {0,5} \right]\).

Show Step 2

Now, we know that the integral is simply the area between the line and the \(x\)-axis and so we should be able to use basic area formulas to help us determine the value of the integral.

In this case we can see the area is clearly a triangle with base 5 and height 20. However, we need to be a little careful here and recall that area that is below the \(x\)-axis is considered to be negative area and so we’ll need to keep that in mind when we do the area computation.

Here is the value of the integral,

\[\int_{0}^{5}{{ - 4x\,dx}} = - \frac{1}{2}\left( 5 \right)\left( {20} \right) = \require{bbox} \bbox[2pt,border:1px solid black]{{ - 50}}\]