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Section 4.12 : Differentials

3. Compute the differential for \(h\left( z \right) = \ln \left( {2z} \right)\sin \left( {2z} \right)\).

Show Solution

There is not really a whole lot to this problem.

\[\require{bbox} \bbox[2pt,border:1px solid black]{{dh = \left( {\frac{1}{z}\sin \left( {2z} \right) + 2\ln \left( {2z} \right)\cos \left( {2z} \right)} \right)dz}}\]

Don’t forget to tack on the \(dz\) at the end!