Paul's Online Notes
Paul's Online Notes
Home / Calculus III / Multiple Integrals / Change of Variables
Show Mobile Notice Show All Notes Hide All Notes
Mobile Notice
You appear to be on a device with a "narrow" screen width (i.e. you are probably on a mobile phone). Due to the nature of the mathematics on this site it is best views in landscape mode. If your device is not in landscape mode many of the equations will run off the side of your device (should be able to scroll to see them) and some of the menu items will be cut off due to the narrow screen width.

Section 4-8 : Change of Variables

6. If \(R\) is the region bounded by \(xy = 1\), \(xy = 3\), \(y = 2\) and \(y = 6\) determine the region we would get applying the transformation \(\displaystyle x = \frac{v}{{6u}}\), \(y = 2u\) to \(R\).

Show All Steps Hide All Steps

Start Solution

Let’s start off with a sketch of \(R\).

The equations of each of the boundaries of the region are given in the sketch. We also included “extensions” of the two curves (the dotted portions) just to show a fuller sketch of the two curves.

Show Step 2

Okay, now all we need to do is apply the transformation to each of the boundary equations. To do this we simply plug the transformation into each of the boundary equations.

Let’s start with \(y = 6\). Applying the transformation to this equation gives,

\[2u = 6\hspace{0.5in} \Rightarrow \hspace{0.5in}\underline {u = 3} \]

So, this boundary will transform into the equation \(u = 3\).

Show Step 3

Let’s now apply the transformation to \(xy = 3\).

\[\begin{align*}\left( {\frac{v}{{6u}}} \right)\left( {2u} \right) & = 3\\ \frac{v}{3} & = 3\hspace{0.5in} \Rightarrow \hspace{0.5in}\underline {v = 9} \end{align*}\]

This boundary transforms in the equation \(v = 9\).

Show Step 4

Next, let’s apply the transformation to \(y = 2\).

\[2u = 2\hspace{0.5in} \Rightarrow \hspace{0.5in}\underline {u = 1} \]

So, this boundary will transform into the equation \(u = 1\).

Show Step 5

Finally let’s apply the transformation to \(xy = 1\).

\[\begin{align*}\left( {\frac{v}{{6u}}} \right)\left( {2u} \right) & = 1\\ \frac{v}{3} & = 1\hspace{0.5in} \Rightarrow \hspace{0.5in}\underline {v = 3} \end{align*}\]

This boundary transforms in the equation \(v = 3\).

Show Step 6

Sketching the transformed equations gives the following region.

So, we transform the odd shaped region into a rectangle under the transformation.

Note that we chose \(u\) to be the horizontal axis and \(v\) to be vertical axis in the transformed region for this problem. There is no real reason for doing that other than it is just what we’ve always done. Regardless of your choices here make sure to label the axes to make it clear!