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Section 15.5 : Triple Integrals
- Evaluate ∫32∫4−1∫014x2y−z3dzdydx∫32∫4−1∫014x2y−z3dzdydx Solution
- Evaluate ∫10∫z20∫30ycos(z5)dxdydz∫10∫z20∫30ycos(z5)dxdydz Solution
- Evaluate ∭E6z2dV∭E6z2dV where EE is the region below 4x+y+2z=104x+y+2z=10 in the first octant. Solution
- Evaluate ∭E3−4xdV∭E3−4xdV where EE is the region below z=4−xyz=4−xy and above the region in the xyxy-plane defined by 0≤x≤20≤x≤2, 0≤y≤10≤y≤1. Solution
- Evaluate ∭E12y−8xdV∭E12y−8xdV where EE is the region behind y=10−2zy=10−2z and in front of the region in the xzxz-plane bounded by z=2xz=2x, z=5z=5 and x=0x=0. Solution
- Evaluate ∭EyzdV∭EyzdV where EE is the region bounded by x=2y2+2z2−5x=2y2+2z2−5 and the plane x=1x=1. Solution
- Evaluate ∭E15zdV∭E15zdV where EE is the region between 2x+y+z=42x+y+z=4 and 4x+4y+2z=204x+4y+2z=20 that is in front of the region in the yzyz-plane bounded by z=2y2z=2y2 and z=√4yz=√4y. Solution
- Use a triple integral to determine the volume of the region below z=4−xyz=4−xy and above the region in the xyxy-plane defined by 0≤x≤20≤x≤2, 0≤y≤10≤y≤1. Solution
- Use a triple integral to determine the volume of the region that is below z=8−x2−y2z=8−x2−y2 above z=−√4x2+4y2z=−√4x2+4y2 and inside x2+y2=4x2+y2=4. Solution