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Section 9.1 : Parametric Equations and Curves
For problems 1 – 6 eliminate the parameter for the given set of parametric equations, sketch the graph of the parametric curve and give any limits that might exist on \(x\) and \(y\).
- \(x = 4 - 2t\hspace{0.5in}y = 3 + 6t - 4{t^2}\) Solution
- \(x = 4 - 2t\hspace{0.5in}y = 3 + 6t - 4{t^2}\hspace{0.5in}0 \le t \le 3\) Solution
- \(\displaystyle x = \sqrt {t + 1} \hspace{0.5in}y = \frac{1}{{t + 1}} \hspace{0.5in} t > - 1\) Solution
- \(x = 3\sin \left( t \right)\hspace{0.5in}y = - 4\cos \left( t \right) \hspace{0.5in} 0 \le t \le 2\pi \) Solution
- \(x = 3\sin \left( {2t} \right)\hspace{0.5in}y = - 4\cos \left( {2t} \right) \hspace{0.5in}0 \le t \le 2\pi \) Solution
- \(\displaystyle x = 3\sin \left( {\frac{1}{3}t} \right)\hspace{0.5in}y = - 4\cos \left( {\frac{1}{3}t} \right) \hspace{0.5in}0 \le t \le 2\pi \) Solution
For problems 7 – 11 the path of a particle is given by the set of parametric equations. Completely describe the path of the particle. To completely describe the path of the particle you will need to provide the following information.
- A sketch of the parametric curve (including direction of motion) based on the equation you get by eliminating the parameter.
- Limits on \(x\) and \(y\).
- A range of \(t\)’s for a single trace of the parametric curve.
- The number of traces of the curve the particle makes if an overall range of \(t\)’s is provided in the problem.
- \(x = 3 - 2\cos \left( {3t} \right)\hspace{0.5in}y = 1 + 4\sin \left( {3t} \right)\) Solution
- \(x = 4\sin \left( {\frac{1}{4}t} \right)\hspace{0.5in}y = 1 - 2{\cos ^2}\left( {\frac{1}{4}t} \right) \hspace{0.5in} - 52\pi \le t \le 34\pi \) Solution
- \(\displaystyle x = \sqrt {4 + \cos \left( {\frac{5}{2}t} \right)} \hspace{0.5in}y = 1 + \frac{1}{3}\cos \left( {\frac{5}{2}t} \right) \hspace{0.5in} - 48\pi \le t \le 2\pi \) Solution
- \(\displaystyle x = 2{{\bf{e}}^t}\hspace{0.5in}y = \cos \left( {1 + {{\bf{e}}^{3t}}} \right) \hspace{0.5in} 0 \le t \le \frac{3}{4}\) Solution
- \(\displaystyle x = \frac{1}{2}{{\bf{e}}^{ - 3t}}\hspace{0.5in}y = {{\bf{e}}^{ - 6t}} + 2{{\bf{e}}^{ - 3t}} - 8\) Solution
For problems 12 – 14 write down a set of parametric equations for the given equation that meets the given extra conditions (if any).
- \(y = 3{x^2} - \ln \left( {4x + 2} \right)\) Solution
- \({x^2} + {y^2} = 36\) and the parametric curve resulting from the parametric equations should be at \(\left( {6,0} \right)\) when \(t = 0\) and the curve should have a counter clockwise rotation. Solution
- \(\displaystyle \frac{{{x^2}}}{4} + \frac{{{y^2}}}{{49}} = 1\) and the parametric curve resulting from the parametric equations should be at \(\left( {0, - 7} \right)\) when \(t = 0\) and the curve should have a clockwise rotation. Solution